Basic Math  New Program since October 2002
Any Section, Applying the Concepts area.
These problems may be omitted because they are too advanced for most students and will hold up progress in many circumstances.
Section 1.3, problem 67.
The answer in the solutions guide should be 49,624 rather than 49,627.
Section 1.6, problem 39.
In the solutions guide the the first expression should be 6  3 + 2 rather than 6 3 + 3.
Section 2.7, problem 9.
In the solutions guide, the numerator of the improper fraction in the nexttolast should be 585 rather than 584. The mixed number answer is correct as printed.
Section 2.7, problem 85.
In the solutions guide the denominator of the first fraction should be 17 rather than 77. The mistake is corrected in the third step.
Section 2.8, problem 18.
In the Solutions Guide, the first step is correct but the other steps do not correspond with this problem. The correct answer is 3/125.
Chapter 2 Test, #14.
The textbook does not include the fraction to be changed. Following the directions should be the equation:
5/8 = ___/72
Section 3.2, problems 31 and 32.
Problem 31. The answer in the solutions guide includes Lunch meat and it should not. Without the Lunch meat, the answer is Yes, $10 is enough money.
Problem 32. The answer in the solutions guide is incorrect because the sum is not between $7 and $8.
Section 3.3, problem 40.
The answer in the solutions guide should be 31.6 rather than 30.6.
Section 3.4, problem 134c. The number of hours, 38.5, should be multiplied times $36.75 rather than $26.75. The correct answer is $1414.88
.
Section 3.5, problem 37. In the solutions guide, the divisor is incorrect so the digits in the process are incorrect. However, the rounded answer is correct.
Section 3.5, problem 39. In the solutions guide, the divisor is incorrect so the digits in the process are incorrect. However, the rounded answer is correct.
Chapter 3 Test, #3.
The problem is listed incorrectly in the solutions guide and the answer is incorrect. The correct answer is 4.087.
Chapter 5 Test, #4.
In the solutions guide, when multiplying by 100 the decimal should move two positions to the right so the correct answer is 163%.
Section 6.1. problem 1.
The instructions say to round to the nearest tenth of a cent. One cent is one hundredth (0.01 of a dollar, so one tenth of a cent (one tenth of one hundredth) is one thousandth (0.001) of a dollar and that is the accuracy of the answer, $0.055.
Section 6.1. problem 5.
In the solutions guide, when 0.0798 is rounded to the thousandths place, the answer is $0.080 rather than $0.0080.
Section 6.1. problem 8.
When you round 0.0798 to the thousandths place, the answer is $0.080 rather than $0.0080.
Section 7.5, problem 11. The probability of throwing a sum of 10 should be 3/36 or 1/12 rather than 1/36. However, the answer remains the same since 1/9 > 1/12.
Section 9.2, problem 55. The problem in the solutions guide is not the same as the problem in the textbook. To solve the problem, factor the radicand into t^{4} • t^{2}, then take the fourth root of the two factors separately. The 4th root of t^{4} is t and t^{2} remains under the radical.
Section 9.5, problem 28. In the solutions guide, the cost per pound is given as $5 / kg, but the problem says the cost is $10 / kg. To convert to cost per pound, multiply ($10 / kg) x (1 kg / 2.2 lb) to get $4.55 / lb.
Final Exam, page 563 textbook.
Please work problems 134 (and omit 3560). The Chalk Dust textbook includes Chapters 19. The host Houghton Mifflin textbook also contained chapters 1012 which were omitted, along with pages 393562 which are missing from our text because those pages supported the last three chapters. The Solutions Manual does not have problems 134 because they were part of the chapters that were omitted. However, the answers to problems 134 are as follows.
1. 3259
2. 53
3. 16
4. 144
5. 1 49/120
6. 3 29/48
7. 6 3/14
8. 4/9
9. 1/6
10. 1/13
11. 164.177
12. 60,205
13. 0.027918
14. 0.69
15. 9/20
16. 24.5 mi/gal
17. 54.9
18. 9/40
19. 135%
20. 125%
21. 36
22. 133 1/3%
23. 70
24. 20 in.
25. 1 ft 4 in.
26. 2.5 lb
27. 6 lb 6 oz
28. 2.25 gal
29. 1 gal 3 qt
30. 248 cm
31. 4.62 m
32. 1.614 kg
33. 2067 ml
34. 88.55 km
Please utilize "technical support" if you have specific questions about the final exam.
Basic Math  Previous Programs
Textbook, Preface.
Your Basic Math program is complete with the text, student solutions guide, and technical support from Chalk Dust Company(Dana Mosely) and no additional materials are needed.
Section 1.2, problem 62, page 15; when estimating problem #62 why round two
numbers to zero.
Two of the numbers rounded to 0 because they were closer to 0 than to 10,000
. Remember, the directions say to round to the nearest 10,000. Another
example like that would be rounding the number 1 to the nearest 10. The
answer would be 0 because 1 is closer to 0 than to 10. Concerning rounding
82,984 to the nearest tenthousand you underline the tenthousandths digit
which is the 8, and look at the 2.
Section 2.1, problem 31, page 63.(Page 65 for the 5th edition)
To find the Least Common Multiple for 9, 36, and 64, first write each
number as a product of prime numbers; that product is called a prime
factorization:
9 = 3 (3)
36 = 2 (2) (3) (3) Note: 2 factors of 2 AND 2 factors of 3
64 = 2 (2) (2) (2) (2) (2) Note: 6 factors of 2
The LCM contains every different KIND of factor that you see in any of
the prime factorizations (that means the LCM will contain factors of 2 and 3
only), AND the LCM will contain those factors the MOST number of times they
appear in any prime factorization so the factor 2 will appear 6 times and
the factor 3 will appear 2 times. See example 1 on page 61. For this
problem, that means LCM = 2 (2) (2) (2) (2) (2) (3) (3) and after
multiplying the factors
LCM = 576.
Section 2.6, problem 119, page 96. Omit this problem. Old program only, 4th edition textbook.
Section 4.3, problem 73. Old program only, 4th edition textbook
Here is a proportion method that is different from the one in the
solutions manual. Set up the proportion according to the following idea: 3
shares to 5 shares is proportionate to 240 shares to x shares; or 3/5 =
240/x. Solving for x you get 400 shares as expected.
Section 5.3, problem 38, page 208. Omit this problem.
Section 9.5, problem 28. In the solutions guide, the cost per pound is given as $5 / kg, but the problem says the cost is $10 / kg. To convert to cost per pound, multiply ($10 / kg) x (1 kg / 2.2 lb) to get $4.55 / lb.
